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Physiology · Respiratory: surfactant and alveolar stability
Sample itemWithout surfactant, two connected alveoli of different radii have the same surface tension. According to the Laplace relation, what happens, and how does surfactant help?
Original practice item, not a recalled exam question. Nothing here is recorded.
The answer and the reasoning
A. Pressure is higher in the smaller alveolus, so it empties into the larger one; surfactant lowers tension more in the smaller alveolus
Laplace law for a sphere gives pressure equal to 2T divided by r, so at equal tension a smaller alveolus has a higher pressure and tends to collapse into the larger one. Surfactant (dipalmitoylphosphatidylcholine) is concentrated as the alveolus shrinks, so it reduces tension more in the smaller alveolus and stabilises it. It also raises compliance and keeps alveoli dry.
Option by option
A. Pressure is higher in the smaller alveolus, so it empties into the larger one; surfactant lowers tension more in the smaller alveolus (correct)
Correct. Inverse radius dependence plus density-dependent action stabilises small alveoli.
B. Pressure is higher in the smaller alveolus, so it empties into the larger one; surfactant increases tension in the larger alveolus
Surfactant reduces tension and never raises it.
C. Pressure is equal in both, so flow does not occur; surfactant is needed only for compliance
Pressures differ with radius, so collapse of small alveoli is the real problem.
D. Pressure is higher in the larger alveolus, so it empties into the smaller one; surfactant lowers tension equally in both
Pressure is inversely proportional to radius, so the smaller alveolus has the higher pressure.
Source note: Original NextPrep sample item — pending expert review. This item is original practice material awaiting independent expert review, so confirm important facts in a standard textbook.
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