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Physiology · Renal: Starling forces in glomerular filtration
Sample itemIn a patient, glomerular capillary hydrostatic pressure is 60 mmHg, plasma oncotic pressure in the capillary is 32 mmHg and Bowman space pressure is 18 mmHg. A ureteric stone then raises Bowman space pressure to 28 mmHg with other forces unchanged. What happens to the net filtration pressure?
Original practice item, not a recalled exam question. Nothing here is recorded.
The answer and the reasoning
A. It falls from 10 mmHg to about 0 mmHg, so filtration nearly ceases
Net filtration pressure equals glomerular hydrostatic pressure minus the sum of plasma oncotic pressure and Bowman space pressure. At first it is 60 minus (32 + 18), which gives 10 mmHg, and after obstruction it is 60 minus (32 + 28), which gives 0 mmHg. Thus GFR falls towards zero in acute obstruction.
Option by option
A. It falls from 10 mmHg to about 0 mmHg, so filtration nearly ceases (correct)
Correct. A 10 mmHg rise in back pressure abolishes the net driving force.
B. It falls from 10 mmHg to minus 10 mmHg, so fluid is absorbed from Bowman space
The calculation gives 0 mmHg, not minus 10 mmHg.
C. It remains 10 mmHg, because hydrostatic pressure in the capillary is unchanged
Bowman space pressure is one of the Starling forces and changes the net pressure.
D. It rises from 10 mmHg to 20 mmHg
Bowman space pressure opposes filtration, so raising it cannot increase the net pressure.
Source note: Original NextPrep sample item — pending expert review. This item is original practice material awaiting independent expert review, so confirm important facts in a standard textbook.
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