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Physiology · Respiratory system: helium dilution
Sample itemIn a closed-circuit helium dilution test, a 4 L spirometer contains 8% helium. After the patient rebreathes from it at the end of a normal expiration, the helium concentration equilibrates at 5%. What is the patient's functional residual capacity?
Original practice item, not a recalled exam question. Nothing here is recorded.
The answer and the reasoning
B. 2.4 L
The amount of helium is conserved as it mixes into the lungs, so C1 x V1 = C2 x (V1 + FRC). Thus 0.08 x 4 = 0.05 x (4 + FRC), which gives 4 + FRC = 6.4 and FRC = 2.4 L. The method measures only gas communicating with the airways, so it underestimates FRC with air trapping.
Option by option
A. 4.0 L
4.0 L is the spirometer volume, which does not include the lung gas.
B. 2.4 L (correct)
0.32 = 0.05 x (4 + FRC), so FRC = 6.4 - 4 = 2.4 L.
C. 1.6 L
1.6 L is simply the ratio 8/5 and ignores the spirometer volume.
D. 6.4 L
6.4 L is the final combined volume; the spirometer volume must still be subtracted.
Source note: Original NextPrep sample item — pending expert review. This item is original practice material awaiting independent expert review, so confirm important facts in a standard textbook.
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