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Physiology · Renal: renal blood flow and filtration fraction
Sample itemA man has para-aminohippurate clearance of 600 mL/min, inulin clearance of 120 mL/min and haematocrit 40%. What are his filtration fraction and renal blood flow?
Original practice item, not a recalled exam question. Nothing here is recorded.
The answer and the reasoning
B. Filtration fraction 0.20; renal blood flow 1000 mL/min
PAH clearance estimates effective renal plasma flow (600 mL/min) and inulin clearance estimates GFR (120 mL/min). Filtration fraction = GFR / RPF = 120 / 600 = 0.20. Renal blood flow = RPF / (1 - haematocrit) = 600 / 0.6 = 1000 mL/min.
Option by option
A. Filtration fraction 0.12; renal blood flow 1000 mL/min
0.12 comes from dividing GFR by blood flow instead of plasma flow.
B. Filtration fraction 0.20; renal blood flow 1000 mL/min (correct)
Correct. 120/600 gives 0.20 and 600/0.6 gives 1000 mL/min.
C. Filtration fraction 0.20; renal blood flow 600 mL/min
600 mL/min is the plasma flow, and blood flow must include the red cell fraction.
D. Filtration fraction 0.20; renal blood flow 1500 mL/min
1500 mL/min arises from dividing by the haematocrit (0.4) instead of one minus the haematocrit.
Source note: Original NextPrep sample item — pending expert review. This item is original practice material awaiting independent expert review, so confirm important facts in a standard textbook.
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