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Pharmacology · Toxicology and antidotes: isopropyl alcohol poisoning
Sample itemA man found drowsy with a fruity odour on his breath has normal blood glucose and strongly positive serum ketones. Arterial pH is 7.38 with normal bicarbonate, the osmolar gap is raised, and he has no visual symptoms. Which ingestion is most likely?
Original practice item, not a recalled exam question. Nothing here is recorded.
The answer and the reasoning
C. Isopropyl alcohol
Isopropyl alcohol is metabolised by alcohol dehydrogenase to acetone, which causes ketosis without significant acidosis, and the parent alcohol raises the osmolar gap. Methanol and ethylene glycol produce a high anion gap metabolic acidosis, with visual loss or crystalluria respectively.
Option by option
A. Methanol
Methanol produces formic acid, severe anion gap acidosis and visual loss.
B. Ethylene glycol
Ethylene glycol produces oxalic acid, acidosis, hypocalcaemia and renal failure.
C. Isopropyl alcohol (correct)
Correct. Ketosis without acidosis with an osmolar gap points to isopropyl alcohol.
D. Propylene glycol
Propylene glycol causes lactic acidosis, and acetone ketosis is not a feature.
Source note: Original NextPrep sample item — pending expert review. This item is original practice material awaiting independent expert review, so confirm important facts in a standard textbook.
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