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Biochemistry · Glycolysis: arsenate poisoning
Sample itemA farm worker accidentally ingests a pesticide containing sodium arsenate. Red cell glycolysis is studied in vitro. Arsenate substitutes for inorganic phosphate in the glyceraldehyde-3-phosphate dehydrogenase reaction. What is the net effect on ATP produced by glycolysis from one glucose molecule?
Original practice item, not a recalled exam question. Nothing here is recorded.
The answer and the reasoning
B. Zero net ATP, because the arseno-compound hydrolyses spontaneously and bypasses phosphoglycerate kinase
Arsenate forms 1-arseno-3-phosphoglycerate, which is unstable and hydrolyses non-enzymatically to 3-phosphoglycerate. The step that normally yields ATP through phosphoglycerate kinase is bypassed, so the two ATP made in the pay-off phase are lost. Two ATP are still spent in the investment phase, so the net yield is zero; this is critical in red cells, which rely solely on glycolysis.
Option by option
A. Zero net ATP, because pyruvate kinase is directly inhibited by arsenate
The block is at the phosphoglycerate kinase step, and arsenate does not directly inhibit pyruvate kinase.
B. Zero net ATP, because the arseno-compound hydrolyses spontaneously and bypasses phosphoglycerate kinase (correct)
Correct. Bypass of phosphoglycerate kinase cancels the pay-off ATP, leaving no net gain.
C. Two net ATP, since hexokinase and phosphofructokinase steps are unaffected
Two ATP is the normal net yield and ignores the loss of the pay-off from the 1,3-bisphosphoglycerate step.
D. Four net ATP, because substrate-level phosphorylation is increased
Substrate-level phosphorylation is bypassed, not increased, so there cannot be extra ATP.
Source note: Original NextPrep sample item — pending expert review. This item is original practice material awaiting independent expert review, so confirm important facts in a standard textbook.
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