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Pathology · Apoptosis: BCL-2 family
Sample itemA 55-year-old man has painless generalised lymphadenopathy and a lymph node biopsy shows a nodular proliferation of small cleaved cells. Cytogenetics show t(14;18). What is the consequence of this translocation?
Original practice item, not a recalled exam question. Nothing here is recorded.
The answer and the reasoning
B. Overexpression of BCL-2, blocking mitochondrial apoptosis and prolonging B-cell survival
In follicular lymphoma, t(14;18) places the BCL2 gene next to the immunoglobulin heavy chain enhancer, causing overexpression of BCL-2. BCL-2 prevents BAX and BAK from permeabilising the mitochondrial membrane, so cytochrome c is not released and cells fail to undergo apoptosis. The tumour is therefore driven by survival rather than rapid proliferation.
Option by option
A. Constitutive tyrosine kinase activity from a fusion gene
A constitutively active tyrosine kinase fusion is the mechanism of BCR-ABL in chronic myeloid leukaemia.
B. Overexpression of BCL-2, blocking mitochondrial apoptosis and prolonging B-cell survival (correct)
Correct. BCL-2 is an anti-apoptotic protein that keeps lymphoma cells alive.
C. Overexpression of cyclin D1, driving cell cycle entry
Cyclin D1 overexpression results from t(11;14) in mantle cell lymphoma.
D. Loss of p53 function, preventing DNA damage responses
TP53 loss is a separate event and is not the product of t(14;18).
Source note: Original NextPrep sample item — pending expert review. This item is original practice material awaiting independent expert review, so confirm important facts in a standard textbook.
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